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Evaluate the piecewise defined function at the indicated values.

$$

\begin{array}{ll}{f(x)=\left\{\begin{array}{ll}{5} & {\text { if } x \leq 2} \\ {2 x-3} & {\text { if } x>2}\end{array}\right.} \\ {f(-3), f(0), f(2),} & {f(3), f(5)}\end{array}

$$

$f(-3)=5$

$f(0)=5$

$f(2)=5$

$f(3)=3$

$f(5)=7$

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Okay, so we want to evaluate each of these following terms here. So it's notice here that are F. Lex is a piece of dysfunction when X is less than or equal to dough or left with to. Our function is just equal to yes. So it's fine all over ex terms that are less than or equal to two. To show that system here, that's negative. Three. That's going to be five. This is going to be five, and then arrests are greater into which has the function to X minus three. So that's two times two minus three, which is four ministry. So that's equal to one. And then here we have two times three minus two bay, which is equal to six months three. And that's equal to three. And then we have two times five minus three. So that's equal to a 10 minus three, which is equal to seven

University of California, Berkeley

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