Question
Evaluate the terms of $\sum_{i=1}^{4} f\left(x_{i}\right) \Delta x,$ with $x_{1}=0, x_{2}=2, x_{3}=4, x_{4}=6,$ and $\Delta x=0.5,$ for each function. $$f(x)=6+2 x$$
Step 1
This gives us the following values: $$f(x_{1}) = f(0) = 6 + 2*0 = 6$$ $$f(x_{2}) = f(2) = 6 + 2*2 = 10$$ $$f(x_{3}) = f(4) = 6 + 2*4 = 14$$ $$f(x_{4}) = f(6) = 6 + 2*6 = 18$$ Show more…
Show all steps
Your feedback will help us improve your experience
Ankit Gupta and 70 other Algebra 2 educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Evaluate the terms of $\sum_{i=1}^{4} f\left(x_{i}\right) \Delta x,$ with $x_{1}=0, x_{2}=2, x_{3}=4, x_{4}=6,$ and $\Delta x=0.5,$ for each function. $$f(x)=\frac{-2}{x+1}$$
Further Topics in Algebra
Sequences and Series
Evaluate the terms of $\sum_{i=1}^{4} f\left(x_{i}\right) \Delta x,$ with $x_{1}=0, x_{2}=2, x_{3}=4, x_{4}=6,$ and $\Delta x=0.5,$ for each function. $$f(x)=x^{2}-1$$
Evaluate the terms of $\sum_{i=1}^{4} f\left(x_{i}\right) \Delta x,$ with $x_{1}=0, x_{2}=2, x_{3}=4, x_{4}=6,$ and $\Delta x=0.5,$ for each function. $$f(x)=2 x^{2}$$
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD