00:01
Okay, so for this problem, we're taking the integral of ln of x divided by x squared.
00:05
So we're going to be using integration by parts.
00:08
So the first step is going to be to identify what our u is and what our dv is.
00:14
So for this problem, it's best to choose ln of x as u.
00:19
So that means that our dv is going to be 1 over x squared.
00:32
So now that we've established this, let's find d ,u, and v.
00:36
So to find du, we just take the derivative of both sides.
00:39
So our du is going to be equal to 1 over x, dx.
00:49
For dv, we're going to take the integral of both sides.
00:52
So this is actually also equal to x to the negative second power...