00:01
Okay, this question wants us to find the six trig functions of an angle ending at this point.
00:07
So we'll start just by drawing a triangle, and it's negative 5 .4 for the x -cordinate, so we'll draw it to the left, making it negative to help us with signs, and then the y -corident is 7 .2.
00:37
And we care about this angle theta right here.
00:43
So first, before we can start, we're going to have to calculate.
00:46
The value of the hypotenuse since we're going to need that.
00:55
So we know that for this triangle, r squared is equal to 5 .4 squared plus 7 .2 squared.
01:11
So r would be equal to the square root of this.
01:17
And actually, this thing under the square root just ends up to be 81.
01:22
So r is just equal to 9 because it's a perfect square.
01:27
So we can actually fill that in up here.
01:35
And now that we have this, we can just fill in all our six trig functions.
01:41
So sine theta is equal to opposite over hypotenuse, so 7 .2 divided by 9...