00:01
At times they give us this formula, a of t is equal to 699 all over t plus 1 to the .94 power.
00:16
Now, if i were doing this problem, i would actually rewrite this as 699 times t plus 1 to the negative .94 power.
00:26
So that makes it easier for me to take the derivative using the chain rule and i can move the exponent front.
00:34
Just typing a 0 .94 times 699 is negative 657 .06.
00:46
You leave the interfunction alone, but you have to subtract 1 from that exponent, so negative 0 .94 minus 1 is negative 1.
01:00
And then you do have to take the derivative of the inside and multiply it, but the derivative of t plus 1 is just 1.
01:07
But now we're ready to find the first part, which is a prime of zero.
01:12
And if you're curious why we're starting with zero, is it says since 2002 and then it asked for 2002.
01:19
So since 2002 would be zero years.
01:22
And if you plug zero in for t, that's what we're doing here.
01:27
0 plus 1 is 1...