Question
Every second at Niagara Falls, some $5000 \mathrm{~m}^{3}$ of water falls a distance of $50.0 \mathrm{~m}$ (Fig. $\mathrm{P} 22.48)$. What is the increase in entropy per second due to the falling water? (Assume that the mass of the surroundings is so great that its temperature and that of the water stay nearly constant at $20.0{ }^{\circ} \mathrm{C}$. Suppose that a negligible amount of water evaporates.)
Step 1
The work done by the falling water is given by the equation $W = mgh$, where $m$ is the mass of the water, $g$ is the acceleration due to gravity, and $h$ is the height of the fall. Show more…
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Every second at Niagara Falls, some 5000 $\mathrm{m}^{3}$ of water falls a distance of $50.0 \mathrm{m} .$ What is the increase in entropy per second due to the falling water? Assume the mass of the surroundings is so great that its temperature and that of the water stay nearly constant at $20.0^{\circ} \mathrm{C} .$ Also assume a negligible amount of water evaporates.
Every second at Niagara Falls, approximately $5000 \mathrm{~m}^{3}$ of water falls a distance of $50.0 \mathrm{~m}$. What is the increase in entropy per second due to the falling water? Assume the mass of the surroundings is so great that its temperature and that of the water stay nearly constant at $20.0^{\circ} \mathrm{C}$. Also assume a negligible amount of water evaporates.
Every second at Niagara Falls, approximately $5.00 \times 10^{3} {m}^{3}$ of water falls a distance of 50.0 ${m}$ . What is the increase in entropy per second due to the falling water? Assume the mass of the surroundings is so great that its temperature and that of the water stay nearly constant at 20.0°C. Also assume a negligible amount of water evaporates.
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