The formula for Simpson's Rule is given by:
\[
\int_{a}^{b} f(x) dx \approx \frac{h}{3} [f(x_0) + 4f(x_1) + f(x_2)]
\]
where $h = \frac{b-a}{n}$, $x_0 = a$, $x_1 = a + h$, and $x_2 = a + 2h$.
For this problem, $a = 0$, $b = 4$, and $n = 2$. So, $h =
Show more…