00:02
Referring to an example in this section, example 4 .42, for the bivariate normal model for the random variable x, which was the sat critical reading score, and the random variable y, which was the sat mathematics score.
00:20
Define the random variable w to be the sat writing score, the third component of the sat.
00:27
We're told this is a mean of 488 and standard deviation of 114.
00:34
We're asked to assume that x and w, so the critical reading and the writing portions have a bivariate normal distribution, where the correlation coefficient of x and w is .5.
00:51
In part a, we're asked to find the distribution of x plus w.
01:11
Well, we know that x and w are bivariate normal.
01:22
This is what we're given as an assumption.
01:28
It follows that the sum, x plus w, has a univariate normal distribution.
01:38
In particular with a mean of the expected value of x plus w which we call it the expected value of a sum is the same as the sum of expected values so this is the expected value of x plus the expected value of w we're given that the expected value of x previously excuse me was 496 and we're given that the expected value of w is 488 so we have 496 plus 496 plus 496 plus 496 plus 496 plus 488 and this sums up to 984.
02:38
So this is the mean and it has a standard deviation well determined by the variance, so we'll actually find the variance first.
03:06
And the variance of a sum of variables, this is going to be the sum of the variances, so variance of x plus the variance, variance of w plus 2 times the coefficients in x and w, which is 1 and 1, times the covariance of x into w.
03:34
This is the same as the variance of x plus the variance of w, plus 2 times the correlation coefficient row of x and w, times the standard deviation of x and w, times the standard deviation of w, times the standard deviation of w, by the definition of correlation coefficient.
04:01
In substituting, we have that the variance of x, well, the standard deviation of x was 114, so this wouldn't be 114 squared.
04:11
Standard deviation was of w was also 114, and so this is 114 squared, plus 2 times the correlation coefficient row, which we're told, was 0 .5 times the standard deviation of x, which again is 14, or 114 i mean, times the standard deviation of w, which is also 114...