00:01
Here in this given problem, mass of the lead sphere that is given as m is equal to 8 .00 g, its atomic mass, atomic mass number, this is 82 and atomic mass, this is atomic number only, not mass number and atomic mass, this is given as 207 g per mole.
00:59
Charge over this sphere that is minus 3 .20 multiplied by 10 to the power minus 9 coulomb.
01:09
In the first part of the problem, we have to find excess electrons, number of electrons carried by this lead sphere.
01:16
So, using quantization of charge, q is equal to n e, e is the charge carried by an electron.
01:33
So, number of excess electrons over the sphere that will be given by n is equal to q by e.
01:48
This is minus 3 .20 multiplied by 10 to the power minus 9 coulomb divided by charge carried by 1 electron 1 .6 into 10 to the power minus 19 coulomb.
02:01
So, this n comes out to be equal to 2 .0 into 10 to the power n...