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Problem 19

Exercises $15-20$ refer to a triangle. Express th…

Problem 18

Exercises $15-20$ refer to a triangle. Express the ratio of the height to the base in simplest form.
\begin{array}{|c|c|}\hline \text { height } & {1 \mathrm{m}} \\ \hline \text { base } & {85\mathrm{cm}} \\ \hline\end{array}


$20 : 17$



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Video Transcript

a number 18. They give us a triangle where we have the height drawn into the base on Remember. Ah, height in a triangle is always perpendicular to the base. Perpendicular means that forms a right angle. Okay, so they're asking us to find the ratio of the height to the base and symbols form. So we have one meter is the high and we have 85 centimeters is the base. So it wants the height to the base. So is one meter over 85 centimeters. Okay, so you can't have different units here, so you need to know there are 100 centimeters in one meter. So what you can dio is just change the one meter up here. Okay? Toe 100 centimeters. So 100 over 85. At that point, you can divide by the greatest common factor, which is five. And you get 20 over 17. Another way to do the problem is when you have your one meter to 85 centimeters. So one meter over 85 centimeters. Okay. If you want. Since you know that there's, ah 100 centimeter in one meter. Okay. You could change your 85 centimeters. You're 85 centimeters in two meters. However, that seems to get a little bit more confusing for people with the decimals that are involved. But you can also do that. The thing is, by doing that, you'll actually be saying OK, 85 centimeters is equal to 850.85 meters and then in the end you'll be moving over two places to places and you get back to where we started before. So just just on idea in case you want to convert that way. But the way that I showed you first makes a little bit more sense.