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Exercises $15-20$ refer to a triangle. Express the ratio of the height to the base in simplest form. $$\begin{array}{|c|c|}\hline \text { height } & {1 \mathrm{m}} \\ \hline \text { base } & {0.6\mathrm{m}} \\ \hline\end{array}$$

Exercises $15-20$ refer to a triangle. Express the ratio of the height to the base in simplest form. $$\begin{array}{|c|c|}\hline \text { height } & {0.6 \mathrm{km}} \\ \hline \text { base } & {0.8\mathrm{km}} \\ \hline\end{array}$$

Exercises $15-20$ refer to a triangle. Express the ratio of the height to the base in simplest form. $$\begin{array}{|c|c|}\hline \text { height } & {1 \mathrm{m}} \\ \hline \text { base } & {85\mathrm{cm}} \\ \hline\end{array}$$

Exercises $15-20$ refer to a triangle. Express the ratio of the height to the base in simplest form. $$\begin{array}{|c|c|}\hline \text { height } & {8 \mathrm{cm}} \\ \hline \text { base } & {50\mathrm{mm}} \\ \hline\end{array}$$

Exercises $15-20$ refer to a triangle. Express the ratio of the height to the base in simplest form. $$\begin{array}{|c|c|}\hline \text { height } & {40 \mathrm{mm}} \\ \hline \text { base } & {0.2\mathrm{m}} \\ \hline\end{array}$$

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Exercises $15-20$ refer to a triangle. Express the ratio of the height to the base in simplest form. $$\begin{array}{|c|c|}\hline \text { height } & {5 \mathrm{km}} \\ \hline \text { base } & {45 \mathrm{km}} \\ \hline\end{array}$$

$1 : 9$

we know that the ratio would be 5 to 45. They're both divisible by 55 Divided by five was 1 45 by five is nine.

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## Discussion

## Video Transcript

we know that the ratio would be 5 to 45. They're both divisible by 55 Divided by five was 1 45 by five is nine.

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