00:01
Okay, so let's explain the following statements, and the first one is that carbon has four bonds.
00:07
And so if you look at the table, carbon is in group four.
00:14
It's going to have four valence electrons.
00:16
So as a result, it needs to form four bonds to have a complete octet.
00:22
Next one is that, i'm sorry, that's for b.
00:25
But the first one is that it engages in covalent, aside from ionic.
00:32
Bonding.
00:33
So covalent bonding can be divided into really polar and nonpolar.
00:45
So polar is a significant difference in electrone negativity between the two atoms.
00:54
So picture carbon and oxygen for ketone.
00:59
The oxygen is a lot more electrone negative than carbon.
01:02
So the luxury negativity will be shifted to where the oxygen.
01:06
And another example of a covalent bond is non -polar.
01:11
And this exists between carbon and hydrogen.
01:15
So if we draw the structure of butane, we have covalent bonding between the carbons, but also of the hydrogens on the interior, as well as the three hydrogens on the exterior are at the end of the chain.
01:33
So not a significant difference in oxygen negativity between the two atoms, but cavalin really just means sharing, and it's shared unequally in a polar bond due to the difference in oxygen negativity and equally in cavailant.
02:06
The next one is that carbon can't form stable cations or in ions.
02:12
So a cation is a positive charge.
02:14
And if you look at this reaction, let's say we had butene reacting with hbr.
02:24
And the alkyens can be a nucleophile and it's going to depotinate hbr or grab proton.
02:33
And we'll get this carbon cadon intermediate it.
02:37
So this is more stable than a primary carbocetion, but these are generally unstable because they don't really satisfy the octet, but it can be made more stable by having more r -groups, which act as electron dynar groups, so whether it be this methyl or an ethyl.
02:56
So basically the more r -groups that the carbon that has the carbokadine is attached to, the more stable it is.
03:04
So this is going to be less stable than the structure, because we have the addition of this extra r -group, which acts as these are all electron denigroups or edgs and if we compare that to a carbanii which is a negative charge on a carbon so let's say we had perpenin or two perpenin and we react this with a strong base like methoxide so in this reaction the alkene i mean the the carbonyl has the carbon adjacent to the carbonyl is the alpha carbon and the hydrogens on the alpha carbon are very acidic so they can be deprotinated by a strong base.
03:55
And this is really good for joining different compounds together through aldol condensation, an aldal condensation reaction, which can be used further to form a ring.
04:05
But in this case, it's going to deprotonate one of the hydrogens on the africarbon...