Question
Explain how solving $2(x-3)(x-1)=0$ differs from solving $2 x(x-3)(x-1)=0$
Step 1
We can ignore the 2 because it doesn't affect the solutions. So we have $(x-3)(x-1)=0$. This equation is true if either $x-3=0$ or $x-1=0$. Solving these two equations gives us $x=3$ and $x=1$. Show more…
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