00:02
Okay, so this question is asking about how to use a rate law to basically find the instantaneous rate of a reaction.
00:09
Okay, so the example i'm going to use here is basically a second order equation.
00:15
This is probably the most common type of chemical reaction possible.
00:21
Okay, so it's basically there are two components that the concentrations matter, and then you have the rate constant at standard temperature and pressure.
00:30
So basically, here, the rate constant, i'll just arbitrarily set it, say it's like five moles or five per mole seconds.
00:40
Remember, the rate constant always has to have units that match out the molarity units of two concentrations.
00:52
So here we have one molarity, two molarity.
00:55
So we need to have a divide by molarity in the rate constant.
01:03
That way, the answer we'll come out with is in moles per second.
01:08
Or molarity per second in this case.
01:13
Okay...