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Explain how to use the formula for $A(x)$ found in the solution to Example 2 to determine the area between the graph of $y=x^{2}$ and the interval $[3,6]$
area=63
Calculus 1 / AB
Calculus 2 / BC
Chapter 5
INTEGRATION
Section 1
An Overview of the Area Problem
Functions
Limits
Differentiation
Integrals
Integration
Integration Techniques
Continuous Functions
Harvey Mudd College
Baylor University
Idaho State University
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so an example to we found that the area formula for X is equal to one third X to the third. So if I calculate the area at six right, I'm going plug six in. So I get one third, six to the third power and then I can also calculate the area at three, which is one third, three to the third. So what I can do here is I could take one third, six to the third power minus one third, three to the third power, which is the same as one third times The quiet E six to the third times three to the third. Six to the third is to 16. Three to the third is 27 which gives me one third of 1 89 which will give me an area under the curve of 63.
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