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Explain, in terms of linear approximations or differentials, why the approximation is reasonable.

$ \frac {1}{9.98} \approx 0.1002 $

$f(9.98)=1 / 9.98 \approx 0.1-0.01(-0.02)=0.1+0.0002=0.1002$ so the approximation is reasonable.

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we know that f of X is one over acts. Therefore, we know that after prime of 10 plugging into the derivative may have turned to the night of two, which is negative 0.1 Therefore, 9.98 would be 0.1 plus negative 0.1 times Negative. 0.2 is 0.1002