00:01
In this problem, we're going to use the standard form of the equation of a circle to determine if given this equation of a circle, the center is 3 negative 2 and the radius is 2 square with to 3 as claimed in the problem.
00:15
So we are going to start by reordering our variables and putting this general equation into our standard form.
00:22
So we're going to have x squared minus 6x, leave some room to complete the square.
00:26
We're going to have y squared plus 4y leave some room to complete the square and then we're going to add three to both sides of this equation to get our constant on the right side okay to complete the square we take half half of the negative six which is negative three and square it don't forget to balance your equation add nine to both sides take half of the four which is two and square it add four to both sides of the equation.
01:00
So when we factor x squared minus 6x plus 9, it's x minus 3 quantity squared.
01:06
We created it to be that way.
01:08
So it would be in standard form.
01:10
And then when we factor y squared plus 4, y plus 4, we get y plus 2 quantity squared, and that equals 16...