00:01
In this problem, what we're being asked to do is to find the mistake from the given student's work.
00:05
So i typically find it nice and easier if i actually go ahead and solve the problem on my own.
00:10
So let's do that over here on the left.
00:12
So we have 4 over p minus 3 is equal to 2 over 5p.
00:17
Now, in this case, we can't go ahead and cross multiply right now because on the left -hand side, it's not one fraction, it's 2.
00:24
So in order to combine these, we can put 3 over 1, and then if i multiply both the numerator, denominator by p, that's going to leave us with 4 over p minus 3p all over p, and this would be equal to 2 over 5p.
00:39
Well, now that they have a common denominator, we can combine them.
00:42
So that would be 4 minus 3p, all getting divided by p, and this would equal to 2 over 5p.
00:50
Okay, great...