explain-what-is-oxidized-and-what-is-reduced-when-copper-reacts-with-oxygen-to-form-copper-ii-oxid-2

Name: explain what is oxidized and what is reduced when copper reacts with oxygen to form copper ii oxid 2
Uploaded: 2020-10-18
Duration: 3 min 13 s
Channel: Numerade
Description: Explain what is oxidized and what is reduced when copper reacts with oxygen to form copper (II) oxide, CuO.

Question

Explain what is oxidized and what is reduced when copper reacts with oxygen to form copper (II) oxide, CuO.

Vishal Sharma · Accepted Answer

in problem one. What is oxidized introduced when cooperates with the oxygen toe form copper oxide. So this is the direction that can take place so we can balance this equation. So this is the on balancing this equation we get to see you, plus all to that will form toe. See you or so in this reaction, basically cooperate, oxidized. So this reaction in this way we can read it. Us. So in this reaction, this copper is oxidized. So this is the oxidation. And this is the reduction that can take this. This is the reduction. So in this reaction, copper is oxidized because the neutral cooperate, um lost the electron neutral corporate, um, lost the electrons and become positive. Charge Corporan and become positive Charge Corporation. The oxygen atom is reduced because the oxygen atom is reduced because it gains lepton and become negative charge it gains electrons and become and become negative Charge oxygen, iron, negative church oxygen. I am so basically, this is the reaction. So in this reaction, this copper oxide that is formed So here copper is in plus to charge and oxygen is minus two charge. So basically, cooper is, uh in the copper loss off electron can take place and in case off oxygen gain off electron can take place, so observation means loss of electrons and a reduction many gain off Flecktones.

April Berlyoung · Answer

problem. 40 describes copper statues such as the Statue of Liberty begin to appear green after they have been exposed to air. It then continues to describe the redox process, where copper metal reacts with oxygen to form solid copper oxide, which forms a green coating. Then ask this to write the reaction for this redox process and identify what is oxidized and what is reduced. So when copper and air oxygen in the air react, we get a reaction between copper and go to to yield. See you proper oxide. See you two oxide. And so, in order to balance this equation, you need to have, ah to here for, 02 Q Oxygen&#x27;s. And that leaves us with war four coppers. So all right, when we look at the, uh, the change in oxidation numbers will cover first, so we have zero. Uh, and for the oxygen is also zero in, uh, copper oxide. Our oxygen is gonna be a minus two, and then our copper is going to be a, uh needs to be a plus two and each cropper is plus one. And so our copper went from zero two plus one, and our to our oxygen. Excuse me. Went from zero to minus to you. In this case, Uh, the copper waas oxidized and the oxygen was reduced. You can also All right, think of this in terms of which direction the oxidation never went. So the oxidation number increases. That is the component that was oxidized. And it&#x27;s decreases. That means electrons were added, so it was reduced.

David Collins · Answer

in the previous problem. Well, look at all of the reactions and then determine what is being oxidized and what is being produced. And this will be based on the change in oxidation numbers. For the 1st 1 the sodium goes from zero to plus one. So it is oxidized in the chlorine goes from zero to minus one, so it is reduced for the next one. We have carbon going from zero to plus four. So it is oxidized and oxygen going from zero to minus two. So it is reduced for the 3rd 1 We have hydrogen going from +10 and oxygen from negative 2 to 0. So hydrogen is reduced and oxygen is oxidized as its oxidation state increases. For D, this was just a precipitation reaction from the change in oxidation state for the next one. It was just a nasty based reaction. So no change in oxidation state. Then we have chlorine going from plus five to minus one. So it was reduced and oxygen going from minus 2 to 0. Oxidation number increased, so it was oxidized. Then we have hydrogen going from zero oxidation state two plus one chlorine from their oxidation state to minus one hydrogen oxidation state increase. But with oxidized Koreans, oxidation state decrease. So it was reduced. And then the next one was just a simple lasted base reaction change in oxidation numbers for the last one, we have think going from an oxidation state of zero to plus two. So it was oxidized copper going from plus 2 to 0. So the copper waas reduced.

Shazia Naz · Answer

right answer for part. A bromate is oxidized and chlorine is reduced. Yeah, here, grow. Might is oxidized because it is losing in electron, mhm in chlorine. He&#x27;s introduced because it is gaining electrons. So he had brominated subsidized and glory knees reduced answer for part B. Siri, um is oxidized because eat lost electrons and copper is reduced because it gained the electrons. So here Syria is oxidized and copper is already used. Okay, answer for park. Si zinc is oxidized because it is lost Electrons. Electrons are electrons and oxygen is reduced because it gain electrons. Do you to oxygen being more okay, likely to attract electrons. So here drink is oxidized and oxygen is reduced unself our party Sorry, um, is oxidized because it loses an electron and hydrogen. It&#x27;s reduced because it gained again. An electron so here sodium is oxidized during hydrogen is reduced

David Collins · Answer

to determine whether or not a reactant is oxidized or reduced, and again we&#x27;ll just focus on the reactant. Those are the species that can be oxidized or reduced. We need to determine whether or not there is a change in charge or a change in oxidation state. If something is oxidized, there&#x27;s an increase in charge or oxidation state. And if something is reduced, there is a decrease in charge or oxidation state. So for the first reaction, we have to bromide plus C L two goes to bro mean and to chlorides. We see that bro mean here has a minus one charge. While over here it has a charge of zero. That is an increase from minus 1 to 0. So it was oxidized. Chlorine has zero charge here. It has a one minus charge here. So it was decreased, so we would say it was reduced for the next chemical reaction. We see that CE goes from no charge here in its solid neutral form to a charge of three plus. So that&#x27;s an increase. So it was oxidized where copper goes from a charge of two plus down to zero. So it was reduced for the next one. We have zinc and oxygen reacting to form the ionic compounds to oxide. Think to oxide is going to have zinc with a two plus charge and the oxygen the oxide with a to minus charge. So we have a neutral compound, so we see zinc going from 0 to 2 plus. So it was oxidized and oxygen going from zero to minus, so it was reduced for the last one. We have sodium metal reacting with hydrogen ion to produce sodium ion and hydrogen gas. We see that sodium goes from zero to a plus one, so it was oxidized and hydrogen goes from a plus 1 to 0, so it was reduced.

Julie Guaglianone · Answer

problem, 41 is asking us to identify which of the reactant is oxidized in which of the reactions is reduced. So let&#x27;s start on this 1st 1 We see that zinc is by itself, and the charge of the Adam is zero. So if you look over here, zinc becomes positive, which means that it loses electrons. So that means zinc is oxidized and because the chlorine atoms go from zero to negative, becoming more negative means of gaining electrons, so that means it is reduced. But this next one, chlorine again is gaining electrons as it goes from a zero charge to a negative charge. So it&#x27;s reduced. And for this one, sodium stays plus one on both sides, so it is not a part of is not. Oxides were reduced. Broening, however, goes from a negative charged to a zero. That means it is losing electrons, so the bro Ming is oxidized for this next one we have led going from a positive to a zero, which means it&#x27;s becoming more negative, so the lead is reduced and then the oxygen goes from a negative charge to zero, so it&#x27;s becoming less negative. It&#x27;s losing electrons, so that means it&#x27;s oxidized for this last one. We have iron, which goes from a plus three to a two plus two. So that means it is becoming more negative and gaining electrons. So it&#x27;s reduced and we have 10 which is going from plus two plus four, which means it is losing electrons, so it is oxidized.

Problem

Explain what is oxidized and what is reduced when…

Problem 1 Easy Difficulty

Explain what is oxidized and what is reduced when copper reacts with oxygen to form copper (II) oxide, CuO.

Answer

In this reaction, copper is oxidized because the neutral
copper atom loses the electrons and becomes a positively
charged copper ion. Th e oxygen atom is reduced
because it gains electrons and becomes a negatively
charged oxygen ion.

Related Courses

Living by Chemistry

Related Topics

Discussion

Top Chemistry 102 Educators

Lizabeth T.

Stephen P.

Karli S.

Jacquelin H.

Chemistry 102 Courses

Liquids - Intro

Comparison Of Gases Liquids And Solids

Recommended Videos

Watch More Solved Questions in Chapter 21

Video Transcript

Angelica M. Stacy

Living by Chemistry

Lizabeth T.

Stephen P.

Karli S.

Jacquelin H.

Liquids - Intro

Comparison Of Gases Liquids And Solids

What do you need help with?

Textbooks

Ask a question

Courses

AI Tutor

In this reaction, copper is oxidized because the neutralcopper atom loses the electrons and becomes a positivelycharged copper ion. Th e oxygen atom is reducedbecause it gains electrons and becomes a negativelycharged oxygen ion.

Living by Chemistry

Lizabeth T.

Stephen P.

Karli S.

Jacquelin H.

Liquids - Intro

Comparison Of Gases Liquids And Solids

Angelica M. StacyLiving by Chemistry

Lizabeth T.

Stephen P.

Karli S.

Jacquelin H.

In this reaction, copper is oxidized because the neutral
copper atom loses the electrons and becomes a positively
charged copper ion. Th e oxygen atom is reduced
because it gains electrons and becomes a negatively
charged oxygen ion.

Angelica M. Stacy

Living by Chemistry