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Explain what is wrong with a problem that requires finding the derivative of $y=\sin ^{-1}\left(x^{2}+1\right).$

Calculus 1 / AB

Chapter 27

Differentiation of Transcendental Functions

Section 3

Derivatives of the Inverse Trigonometric Functions

Derivatives

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you derivative of y is equal to sine inverse of two x plus one. So we take the derivative and I'll get my time is equal to one over the square of one minus. The inputs were so two X plus one squared. And we need to take the chain around so well supplied by two. Well, this is just simplifying a bit. One minus four x squared my Nance plus for X plus one. But we need to flip the sign of everything. Really? I was negative out in front. So the ones that cancel out and what will have his one over, Let's see the spirit of negative X squared minus x okay.

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