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Explain why the function is discontinuous at the given number $ a $. Sketch the graph of the function.

$ f(x) = \left\{ \begin{array}{ll} x + 3 & \mbox{if $ x \le -1 $} \hspace{40mm} a = -1\\ 2^x & \mbox{if $ x > -1 $} \end{array} \right.$

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03:22

Daniel Jaimes

04:34

Anjali Kurse

Calculus 1 / AB

Chapter 2

Limits and Derivatives

Section 5

Continuity

Limits

Derivatives

Oregon State University

Baylor University

University of Michigan - Ann Arbor

Lectures

04:40

In mathematics, the limit of a function is the value that the function gets very close to as the input approaches some value. Thus, it is referred to as the function value or output value.

In mathematics, a derivative is a measure of how a function changes as its input changes. Loosely speaking, a derivative can be thought of as how much one quantity is changing in response to changes in some other quantity; for example, the derivative of the position of a moving object with respect to time is the object's velocity. The concept of a derivative developed as a way to measure the steepness of a curve; the concept was ultimately generalized and now "derivative" is often used to refer to the relationship between two variables, independent and dependent, and to various related notions, such as the differential.

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Explain why the function i…

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here, we have a piecewise defined function F of x F of x equals X plus three. When X is less than or equal to negative one, that's the red portion of the graph. And then for X greater than negative one F of X is defined to be uh to T D X. That's the blue portion of the grave. Uh This function is clearly uh Discontinuous when x equals -1. Uh to limit of the function as X approaches negative one looks to be about one half. Whereas to limit, let me rephrase that as X approaches negative one from the right side from the positive side, the function seems to be approaching a value close to about a half, whereas if we approach X equals negative one, coming in from the left side, uh to function is approaching a value of two. So the function is discontinuous because the limit of the function as X approaches uh negative one does not exist because the right hand limit as we approach negative one from the right side, uh is not going to be the same as the left hand limit as we approach negative one from the left side, from the negative side. Okay, so uh if a function uh does not have a limit because the right hand limit and the left hand limits are different, this is one half, this is too uh if the right hand limits and the left hand limits are different, the limit does not exist and a function cannot be continuous at a point. If the limit does not exist

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