Question
Explain why the pI of lysine is the average of the $\mathrm{p} K_{\mathrm{u}}$ values of its two protonated amino groups.
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The pI, or isoelectric point, is the pH at which a particular molecule or surface carries no net electrical charge. Show more…
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Explain why the pI of lysine is the average of the $\mathrm{p} K_{\mathrm{a}}$ values of its two protonated amino groups.
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