Question
Explain why the singular values of $A$ are the same as the nonzero eigenvalues of the positive definite square root matrix $S=\sqrt{A^T A}$, defined in Exercise 8.5.27.
Step 1
We have a matrix \( A \) and we are considering \( A^T A \) and its square root \( S = \sqrt{A^T A} \). Note that \( A^T A \) is a symmetric matrix because \( (A^T A)^T = A^T (A^T)^T = A^T A \). Show more…
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