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Explain why unbranched alkenes can form geometric isomers while unbranched alkanes cannot. Does this explanation involve the macroscopic domain or the microscopic domain?
This explanation involves microscopic as these concepts relate to the phenomena at molecular level.
00:40
Aadit S.
Chemistry 102
Chapter 20
Organic Chemistry
Rice University
University of Kentucky
University of Toronto
Lectures
02:35
Why is it that alkanes and…
02:37
00:45
Explain why alkanes don&#x…
01:00
Explain geometric isomeris…
01:04
01:40
Explain why alkynes are mo…
01:20
Write the molecular formul…
03:35
Explain why isomers have d…
00:22
Explain how alkenes differ…
00:55
Why don't alkynes hav…
02:34
Explain why numbers are ne…
02:11
Describe how the molecular…
Alkenes exhibit geometric …
02:39
Alkenes exhibit geometrica…
01:52
Explain why these two mole…
0:00
02:13
Explain why compound A has…
01:09
Among alkenes, alkynes, an…
How are alkanes, alkenes, …
06:08
Can molecules with only si…
doing this podcast. We're taking a look at hydrocarbons again and we will be left gang. Why un branched? Al canes are geometric Isom er's, however, on branched al Keynes. Cannot be. Cannot be geometric. I summers so vastly on Branch al Canes. So these are saturated hydrocarbons on branched Oh, Keene's on saturated hydrocarbons because with the Al Canes, or we have a Sigma Bonds with Al Keane's, we now have the presence of double bonds, which is made up of a Sigma bond. Add a pie bond so it specifically with the Al Canes. We do have free rotation about single bonds. Eso all orientations off. The groups in the arcane are equivalent because they can all rotate. Therefore, we cannot have geometric ice Emma's. However, if we take a look at Keene's now we have locked or perhaps rigid rotation about the double bond. Specifically, that's how we're able to get all says trans eczema. So therefore, we can have geometric ice Emma's because we have that rigidity in the back. Then
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