Question
Express each number as a base raised to an integral power to compute the following:(a) $\frac{(4)(16)(128)}{(2)(64)(256)}$(b) $\frac{(125)(25)(5)}{(625)(125)}$
Step 1
For part (a): - \(4 = 2^2\) - \(16 = 2^4\) - \(128 = 2^7\) - \(2 = 2^1\) - \(64 = 2^6\) - \(256 = 2^8\) Now we can rewrite the expression: \[ \frac{(4)(16)(128)}{(2)(64)(256)} = \frac{(2^2)(2^4)(2^7)}{(2^1)(2^6)(2^8)} \] Show more…
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