00:01
Hello, i hope you're doing well.
00:02
So we have our f of x function here, and we have our k value here.
00:05
We need to get this f of x function in the form x minus k times q of x plus r.
00:17
So in order to do so, we are going to take this f of x function and divide it by x minus k.
00:26
So since k is equal to minus 3, x minus k is going to be x plus 3.
00:31
So we need to use synthetic division to divide these.
00:34
But first, one thing you may notice is that for our numerator, we're missing a constant here at the end.
00:40
We've got x the fourth, x cubed, x squared, and x, but no constant here at the end.
00:45
We need a constant in order to do synthetic divisions.
00:48
We're just going to add a plus zero at the end here.
00:51
So now we are going to take, write down all of the coefficients in this expression in the numerators.
00:58
We've got two, this x cube as a coefficient of one.
01:02
We've got minus 15.
01:06
3 and 0.
01:09
And we're dividing this by our k value, which is minus 3.
01:14
So using synthetic division to divide these, we can carry down this 2.
01:19
We've got 2 times minus 3 gives us minus 6.
01:22
1 minus 6 gives us minus 5.
01:24
Minus 5 times minus 3 gives us 15.
01:27
Minus 15 plus 15 gives us 0.
01:30
0 times minus 3 gives us 0.
01:33
3 plus 0 gives us 3.
01:34
3 times minus 3 is minus 9 and 0 minus 1.
01:37
Minus 9 is minus 9.
01:40
So this right here is our remainder term.
01:43
This is our constant or x is zero term.
01:46
This is our coefficient for x...