Question
Express the complex number in trigonometric form with $0 \leq \theta<2 \pi$$$4-3 i$$
Step 1
The modulus of a complex number $a+bi$ is given by $\sqrt{a^2+b^2}$. So for the given number $4-3i$, the modulus is $\sqrt{4^2+(-3)^2}=\sqrt{16+9}=\sqrt{25}=5$. Show more…
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