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Express the function in the form $ f \circ g $.

$ F(x) = \dfrac{\sqrt[3]{x}}{1 + \sqrt[3]{x}} $

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$$\text { Let } g(x)=\sqrt[3]{x} \text { and } f(x)=\frac{x}{1+x} . \text { Then }(f \circ g)(x)=f(g(x))=f(\sqrt[3]{x})=\frac{\sqrt[3]{x}}{1+\sqrt[3]{x}}=F(x)$$.

01:36

Jeffrey Payo

Calculus 1 / AB

Calculus 2 / BC

Calculus 3

Chapter 1

Functions and Models

Section 3

New Functions from Old Functions

Functions

Integration Techniques

Partial Derivatives

Functions of Several Variables

Johns Hopkins University

Campbell University

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Idaho State University

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