Download the App!
Get 24/7 study help with the Numerade app for iOS and Android! Enter your email for an invite.
Question
Answered step-by-step
Express the function in the form $ f \circ g $.
$ v(t) = \sec (t^2) \tan (t^2) $
Video Answer
Solved by verified expert
This problem has been solved!
Try Numerade free for 7 days
Like
Report
Official textbook answer
Video by Heather Zimmers
Numerade Educator
This textbook answer is only visible when subscribed! Please subscribe to view the answer
01:30
Jeffrey Payo
Calculus 1 / AB
Calculus 2 / BC
Calculus 3
Chapter 1
Functions and Models
Section 3
New Functions from Old Functions
Functions
Integration Techniques
Partial Derivatives
Functions of Several Variables
Missouri State University
Oregon State University
Harvey Mudd College
University of Nottingham
Lectures
04:31
A multivariate function is a function whose value depends on several variables. In contrast, a univariate function is a function whose value depends on only one variable. A multivariate function is also called a multivariate expression, a multivariate polynomial, a multivariate series, or a multivariate function of several variables.
12:15
In calculus, partial derivatives are derivatives of a function with respect to one or more of its arguments, where the other arguments are treated as constants. Partial derivatives contrast with total derivatives, which are derivatives of the total function with respect to all of its arguments.
00:40
Express the function in th…
01:37
01:32
01:03
03:11
01:21
$43-48$ Express the functi…
0:00
00:46
$41-46$ Express the functi…
01:01
Differentiate the given fu…
here we have a function V of tea and we want to think of V A. T as a composition of functions f of G and another way to write that would be f of G of tea with parentheses. And looking at that notation, we can see that g of t is the inside function and f of tea is the outside function. So thinking about it that way we could see that the inside function could be t squared so we could let g of t equal t squared. And so the outside function would be C can't t tangent t And that way, if we found f of G, we could substitute t squared in for tea and we would get the original function v of tea.
View More Answers From This Book
Find Another Textbook