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Express the limit as a definite integral on the given interval.
$ \displaystyle \lim_{n \to \infty} \sum_{i = 1}^n [5(x_i^*)^3 - 4x_i^*] \, \Delta x $, [2, 7]
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00:26
Frank Lin
00:17
Amrita Bhasin
01:03
Stephen Hobbs
Calculus 1 / AB
Chapter 5
Integrals
Section 2
The Definite Integral
Integration
Campbell University
Oregon State University
University of Michigan - Ann Arbor
Lectures
05:53
In mathematics, an indefinite integral is an integral whose integrand is not known in terms of elementary functions. An indefinite integral is usually encountered when integrating functions that are not elementary functions themselves.
40:35
In mathematics, integration is one of the two main operations of calculus, with its inverse operation, differentiation, being the other. Given a function of a real variable (often called "the integrand"), an antiderivative is a function whose derivative is the given function. The area under a real-valued function of a real variable is the integral of the function, provided it is defined on a closed interval around a given point. It is a basic result of calculus that an antiderivative always exists, and is equal to the original function evaluated at the upper limit of integration.
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Express the limit as a de…
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Express the limit as a def…
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$17-20$ Express the limit …
Shown below.
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All right, let's actually move onto the next question. Hopefully, you understood what I explained right here. And you can refer back to this problem any time you want. Okay? Now the question is going to be He's black limit as an approach tested Infinity off the song from my goes toe Want end off when you copy it down correctly. Five x i Q t s cubed minus four x. I squared the entire thing times Delta X, where X is from 2 to 7. And it's the same kind of question, right? This as the form of the definite integral. So let's recap the important parts, the limit and the some. You know, the sigma notation is basically the Greek large s so it makes sense that when you're taking the limit, it becomes this fancy looking s okay, the integration is going to be from A to B. We need to identify what those are. We need to figure out what the function is, the height off that point, and we need to figure out what the excess. And of course, we already know that the Delta X is going to be this guy. Okay, so let's figure out what? My effort axis. Very simple. It's this guy. So we will have the expression five x Q minus four X squared. I already mentioned that the Delta X becomes your DX. I usually don't write it, but some people prefer that you use the parentheses so that it looks better where you know exactly where the integration starts at the Trop. It's quite clear if you put this thing, but some people actually like it better that way. A and B are simply the starting point and the endpoint from 2 to 7. So here is your answer. So, in summary, the Riemann some can be represented as the integral from 2 to 7 of five. X cubed minus four X squared TX and this is how you answer this question?
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