00:01
To solve this absolute value inequality, you're just going to set this up with two different possibilities.
00:08
So the first possibility is exactly what you see is what you get.
00:11
So when you remove the absolute value bars, you just take the inside and you leave the relationship exactly as it is.
00:20
So 1 minus 2x is greater than 3.
00:23
The other possibility is that you're going to have the opposite of that value, right? that means is that the 1 minus 2x stays the same, but you're going to change the greater than to its opposite inequality, less than, and you're going to change the value that it's related to 3 to its opposite value, negative 3.
00:45
So it's kind of like you took this equation to the left and multiplied it by a negative 1, right? and you get the equation on the right.
00:52
And then you're going to solve these two and figure out the possibilities.
00:57
So the way we do that, of course, is we're going to isolate the negative 2x by subtract.
01:01
One from both sides.
01:03
So i'll do that.
01:05
You get negative 2x is greater than 2 on the left hand side.
01:10
And on the right hand side, you're going to get negative 2x is less than negative 4.
01:17
And the next step is going to be to undo times by negative 2.
01:21
So the inverse operation would be to divide by negative 2.
01:23
So you're going to divide by negative 2 across the inequality.
01:27
When you divide by a negative across an inequality, you got to remember to reverse the inequality.
01:32
So what you get is x is not greater than, but less than 2 divided by negative 2, which is negative 1.
01:38
And over here on the other side, you're going to divide by negative 2 across the inequality.
01:43
And you're going to get x is not less than, but greater than.
01:49
And then negative 4 divided by negative 2 is positive 2.
01:52
So the result that you have here is an or relationship because they're going in opposite directions.
01:57
They don't overlap.
01:58
So all the values, the less than negative 1 could work.
02:02
The values that are greater than two could work...