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Factor.$$8 x^{2}\left(c^{2}+c-2\right)-2 x\left(c^{2}+c-2\right)-\left(c^{2}+c-2\right)$$

$(2x-1)(4 x+1)(c-1)(c+2)$

Algebra

Chapter 6

Factoring and Quadratic Equations

Section 3

Factoring Trinomials of the Form $a x^{2}+b x+c 454$

Equations and Inequalities

Quadratic Functions

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Okay, so x factor to fallen. We see that we have C squared plus C minus two in terms. So we'll start by factoring that out. So we get C squared plus C minus two and then eight X squared, minus two x minus one. Okay, well, c squared plus two C minus two is the sequel to see plus two times C minus one. And then now we need to factor out our eight x squared minus two x minus one. So let's use our grouping graphics. Do we have a vehicle to eight? The music alternative to and C is equal to make one to our key number is equal to negative eights. So we need to numbers whose product is equal to that of AIDS and who's some is equal to two didn't choose negative four and two. So we'll rewrite our equation as eight X squared minus four x plus two X and then minus one until factoring our 1st 2 terms. Here beacon factor out a four x So we're left with two X minus one and then that's plus two X it's one. So now that we see, we have two x minus one in common with the factor that out. So finally we have C plus two times C minus one times two x minus one and in times of four x plus one.

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