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Factor each expression.$$\left(4 x^{2}+1\right)^{2}(2 x-1)^{-1 / 2}+16 x\left(4 x^{2}+1\right)(2 x-1)^{1 / 2}$$

$\left(4 x^{2}+1\right)(2 x-1)^{1 / 2}\left[\left(4 x^{2}+1\right)(2 x-1)^{-1}+16 x\right]$

Calculus 3

Chapter 0

Algebra Reference

Section 6

Exponents

Functions of Several Variables

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Do you see that we have a for where? Just one in common as well as a text, but it's one terrible cool factor that up, so we're left with a four x plus one finds a two x minus one Jabbar of negative 1/2 1 half so that's minus one and invest 16 x.

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