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Problem 26

Factor each polynomial. If a polynomial cannot be…

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Problem 25

Factor each polynomial. If a polynomial cannot be factored, write prime. Factor out the greatest common factor as necessary.
$$z^{2}+14 z y+49 y^{2}$$

Answer

$z^{2}+14 z y+49 y^{2}=(z+7 y)^{2}$


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Video Transcript

Rast affected this trying O'Neill here. It has a leading coefficient of one. That means we can look at our 49. So we want to find two factors that multiply together to be 49 and add together to be 14. So that would be seven and seven. So this tells us this can be factored into said plus satellite and said Plus seven, Why? And since both terms, all right, both factors are the same. We can actually write this as that cost seven. Why all squared?

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