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Factor. If an expression is prime, so indicate.$$-6 x^{4}+15 x^{3}+9 x^{2}$$

$-3 x^{2}(2 x+1)(x-3)$

Algebra

Chapter 6

Factoring and Quadratic Equations

Section 3

Factoring Trinomials of the Form $a x^{2}+b x+c 454$

Equations and Inequalities

Quadratic Functions

Campbell University

Baylor University

Idaho State University

Lectures

01:18

Factor. If an expression i…

01:49

01:06

05:19

Factor each expression com…

02:50

02:54

Factor expression complete…

00:52

Factor completely. If a po…

01:45

01:47

03:28

01:24

00:53

01:56

01:22

Factor the expression com…

04:23

01:55

Factor. If a polynomial is…

02:29

gets arrested factor to fallen. Start by factoring out of negative three and a X squared. So yet ex didn't have to minus five X and then minus three. Okay, Now let's use our grouping method. To fact that we have a physical one is equal to negative five. And, cuz, question in history, our key number is equal to negative to be so the product of, um, two numbers should be equal to 93 and there's some should be equal to negative five. Okay, so we'll see that we can use three and one. But our son is not equal to negative five, and it's not attainable. So this is not back Terrible. No, actually, when we factor outs from my first gold efficiently, actually, I want to. So where is actually too? So that means our, um, key numbers actually to attempt unaided three, which they have six. So this gives us think or six year so we can have three and two, and they got it too. We're actually negative six, and we want them to something too negative. Five. Ameliorate. This is kind of messy. So we have negative six sendings of five. So we can use forward to introduce six and one, and we'll take six to be negative. So in that group six Post one gives me negative five. So, in fact, that it's into two X squared minus six X plus X and then minus three. In all times they got three x squared and the fact that a fresh determines that gives me we can't back out to X. So we get extra ministry Plus expert is three. So we have X minus three in common. So we'll put it out. We get two X plus one and then our remaining term.

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