00:03
So the factor using difference of scorers, we have to look at our two terms, term one, term two, and determine if they are perfect squatters.
00:14
So x square is a perfect score of x, and one is a perfect square of one.
00:19
So if we do x squared, we get x squared.
00:22
If we do one squared, we get one.
00:24
So this is an example of the difference, the minus sign, of two perfect squares.
00:31
And whenever we have that, we can pretty much always combine it into a simplistic type formula, a plus b and a times a minus b, with a being the squared of the first term and b being the squared of the second term.
00:53
So for this one, all we have to do is pretty much fill in...