00:01
So for this problem, we have a chemical reaction that includes fermentation, and we want to find, given some amount of glucose, how much ethanol in both grams and liters can be made.
00:11
So we first know that we are starting with 500 .5 .4 grams of glucose.
00:22
Now, the first thing that we need to do is we need to find the molar mass of glucose so that we can then do basic calculations with the stoichiometry of this reaction.
00:31
So, glucose is c6h1206.
00:37
So we have six carbons, which is 12 .01, 12 hydrogens, each which is 1 .08 grams per mole, and six oxygens, which is 16 .0 grams per mole.
00:49
And then, when we add all of those things together, you will get 180 .16 grams per mole.
01:02
And the second thing that we need to do, so this is glucose.
01:04
Is we then need to find the molar mass of the product that we desire, which is ethanol, which is c2h5.
01:18
So for ethanol, we have two carbons, which is 2 times 12 .01.
01:23
We have 6 hydrogens, which is 6 times 1 .008.
01:29
And then finally we have an oxygen, which is 16 .00 gram from all.
01:34
And when we add all of those together, we get 46 .07 grams per mole.
01:44
So now we know the molar masses for both ethanol and glucose, and now we can do some basic stoichiometry...