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# Fidn an equation of the tangent line to the curve at the given point. Illustrate by graphing the curve and the tangent line on the same scree.$y = x - \sqrt{x}, (1,0)$

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Derivatives

Differentiation

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### Video Transcript

yet clear. So enumerators. So we have. Why is equal to X minus square root of X. You take the derivative D Y over DX, we get one minus one over two square root of X, and we plug in one. This becomes equal to 1/2. We used the point slope form. We get 1/2 X minus 1/2. Next, we're going to graph our equation. So we're gonna do our original in black, and I will look something like this then are derivative in red. What? Here is uncommon, sir.

Derivatives

Differentiation

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