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Fidn an equation of the tangent line to the curve at the given point. Illustrate by graphing the curve and the tangent line on the same scree.$ y = x - \sqrt{x}, (1,0) $

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Frank L.

Calculus 1 / AB

Chapter 3

Differentiation Rules

Section 1

Derivatives of Polynomials and Exponential Functions

Derivatives

Differentiation

Campbell University

Baylor University

Boston College

Lectures

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02:31

yet clear. So enumerators. So we have. Why is equal to X minus square root of X. You take the derivative D Y over DX, we get one minus one over two square root of X, and we plug in one. This becomes equal to 1/2. We used the point slope form. We get 1/2 X minus 1/2. Next, we're going to graph our equation. So we're gonna do our original in black, and I will look something like this then are derivative in red. What? Here is uncommon, sir.

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