00:01
So for part a, we're going to use equation 12 .9.
00:05
And we can say that here, this would lead to t times l times sine of theta.
00:12
This would be minus m sub p, gx, the weight minus m sub b, g times l over 2.
00:22
This would equal, of course, zero.
00:24
The system is in static equilibrium.
00:27
This can be written in the form of a straight line.
00:29
So we can say that the tension would be equal to essentially the slope multiplied by x over l plus the essentially the y intercept.
00:45
So slope intercept form, y equals mx plus b.
00:49
Here the slope is going to be equal to m sub pg divided by sign of theta...