Question
Figure $14.53$ shows a network of eight resistors numbered 1 to 8 , each equal to $2 \Omega$, connected to a $3 \mathrm{~V}$ battery of negligible internal resistance. The current in the circuit is
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By symmetry, we can see that no current will flow through the middle branches of the circuit. Therefore, we can remove these branches and redraw the equivalent circuit. Show more…
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Figure, shows a network of eight resistors numbered 1 To 8 , each equal to $2 \Omega$, connected to a $3 \mathrm{~V}$ battery of negligible internal resistance The current $\mathrm{I}$ in the circuit is .... (A) $0.25 \mathrm{~A}$ (B) $0.5 \mathrm{~A}$ (C) $0.75 \mathrm{~A}$ (D) $1.0 \mathrm{~A}$
A battery os 12 V is connected in a circuit having three series-connected resistors having resistances of 4 Ω, 9 Ωand 11 Ωin series . Determine the current flowing through, and the p.d. across the 9 Ωresistor.
A 12 V battery is connected in a circuit having three series-connected resistors having resistances of 4 Ω, 9 Ωand 11 Ωin series . Determine the current flowing through, and the p.d. across the 9 Ωresistor.
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