00:02
Hi! in the given problem, in this block diagram, here this is a principal axis and there is a missing lens.
00:14
We don't know the type of this lens and in front of it there is the plant kept here like this.
00:24
Now a ray starting from the tip of this plant moving like this, it is initially diverging away from the principal axis but after passing through the lens means after refraction it becomes parallel to the principal axis so it must be coming from a point on the principal axis which should be acting like the focus the principal focus of this lens so here width of each block along horizontal is given as 2 .0 so now in the first part of the problem, as the ray which was initially diverging away from the principal axis is becoming parallel to the principal axis after refraction.
01:51
So the lens here should be a converging means a convex lens it should be.
02:06
The answer for the first part of the problem.
02:08
Now in the second part of the problem, as the ray is becoming parallel to the principal axis after refraction, so it must be coming from the principal focus.
02:18
The ray, the principal ray, the first principal ray, should be coming from the principal focus of the lens and its distance as shown in the figure is equal to the length.
02:45
To 9 blocks.
02:55
Therefore, the focal length of this converging lens will be equal to 9 into 2 .0 centimeter means this is 18 .0 centimeter.
03:05
Answer for the second part of this problem...