00:01
For this problem, we're given a figure of the orientation energy of a magnetic dipole in an external magnetic field.
00:12
And when the angle phi is zero, it has a kinetic energy of 6 .7 times 10 to the negative 4 joules.
00:21
And we want to know what is the turning point.
00:25
What is the maximum angle phi that it will rotate to before it turns around and starts rotating.
00:30
The other way.
00:32
So in order to figure this out, we're going to use an energy argument and start by finding the total energy.
00:41
So the total energy that this magnetic dipole has will be its kinetic energy plus the orientation energy.
00:57
At phi equals zero, we're told kinetic energy is 6 .8 .5 .2, we're told kinetic energy is 6 .2.
01:02
7 times 10 to the negative 4 joules.
01:07
And looking at the graph when phi is equal to 0, based on the fact that u sub s is 2 times 10th the negative 4, we can conclude that the orientation energy is negative 5 times 10 to the negative 4 jules.
01:30
And so that means that the total energy is 1 .7 times 10 to the negative 4 joules.
01:39
And energy is going to be conserved as the dipole rotates, and eventually the kinetic energy will be zero...