00:01
This problem covers the concept of free fall and under free fall the vertical displacement that is delta y is given by the initial velocity that is v y into the time of fall plus half of the gravitational acceleration into time of fall square so for part a where t equals 50 milliseconds so in that the vertical displacement of the scale is equivalent to the initial speed is zero, so we neglect this term.
00:36
So the vertical displacement is half of the gravitational acceleration, that is 9 .8 meters per second square into time square and time is 50 into 10 minus 3 seconds square.
00:53
Or the vertical displacement or the fall in the scale is equivalent to 0 .0122 meter.
01:03
Or we can see the vertical displacement is equivalent to 1 .22 centimeter.
01:10
So for 50 milliseconds mark the scale reading is 1 .2 centimeter.
01:19
For part b at t equals 100 milliseconds, the vertical displacement that is delta y equals half of 9 .8 meters per second square into time square and that is 0 .1 seconds square or the vertical displacement of the scale is 0 .049 meter or we can say 4 .9 centimeter.
01:58
Now for t equals 150 milliseconds, for t equals 150 milliseconds, the vertical displacement is equivalent to of 9 .8 meters per second square into 0 .150 seconds square.
02:23
Or the scale reading corresponding to that time is equivalent to 0 .11 meter or we can say 11 centimeter.
02:34
At t equals 200 milliseconds, the vertical displacement delta y equals half of 9 .8 meters.
02:44
4 seconds square into 0 .2 seconds square or the vertical displacement of the scale equals 0 .196 meter or we can say 19 .6 centimeter...