00:01
So in this question, we're trying to find out how far away from the track the particle will hit the floor when it flies off at point b here, where it becomes horizontal.
00:10
So the first thing we need to do is apply conservation of energy because we know that the sum of the potential and kinetic energy initially is equal to the sum of potential and kinetic energy in the final state.
00:22
So the potential energy in the initial state is equal to m g times by one because it's at a height of one metre.
00:32
And because it starts from rest, the kinetic energy here is equal to zero, so plus zero, is equal to mg times 0 .5 in this case for the potential, as it's at the height of 0 .5 meters, plus 1 .5 mv squared, which is the kinetic energy at this point b, as we do not know what the velocity is yet.
01:01
So this is our first equation here.
01:04
So we then know that mg is equal.
01:11
To one half m g plus one half mv squared.
01:24
And here these ms can be cancelled, as can be seen.
01:31
And this one half g can be subtracted from the other side so that we obtain an expression for just v squared...