00:01
In this question, we have a block with mass of 2 kilograms resting on an incline slope, which has an incline of 37 degrees.
00:08
There is a spring fixed at the bottom of this incline.
00:11
When the block is released, it slides down the slope and compresses the spring by a distance of 0 .2 metres.
00:17
What we want to find is the coefficient of friction between this block and the slope, and we want to find the spring constant of the spring.
00:25
So in order to do the first part of this question, we can apply the work energy principle for the down.
00:30
Motion of the body.
00:32
We know that initially all of its energy is stored as gravitational potential energy, and if we take the bottom point to have zero gravitational potential energy, we know that at this point all of the energy is elastic potential energy.
00:45
However, some energy has been lost between the start and final position due to the work done against friction.
00:52
So what we can say is that mg, and we must resolve this component parallel to the slope, so as we can see here, this angle is equal to 37 as well, so this component is sign 37.
01:11
So this is the force, but we must multiply by the distance, which is 4 .8 times 0 .2, to obtain the work done.
01:20
And this must be equal to the work done against friction, where the frictional force is given by muar.
01:26
So again, multiply by the distance, we've got 5 mu .r, plus the elastic potential energy due to the compression of the spring, which is given by 1⁄2.
01:38
X squared...