00:01
So for this question, we have given a figure and that shows strain stress graph, okay? strain, stress graph, okay? so from the graph, we have to determine first part a, young's modulus, that is y, and second part b, we have to determine approximately yield strength, okay? eil strength of the material.
00:26
So, from the graph, first of all, to find the y that is yngs modulus, we have to take two points, two points which have known values, two points of known values, and because this is strain, stress graph, okay? so by taking the ratio that is slope, we can get easily the y, okay, because y is equals to stress divided by strain, and from the graph, we can see that this is the slope, nothing else but it is slow okay so from the graph we can identify the values that stress it has a value of 150 multiplied by 10 to the power 6 newton meter minus 2 and strain it can be taken first of all we need to take care that both point must be the both values must be of a single point okay and strain is it 0 .002 now so substituting these two values, stress and strain here, so we can get y it is equals to 150 multiplied by 10 to the power 6 divided by 0 .002.
01:37
Okay, so from here after solving young's modulus y of the material comes out to be 7 .5 multiplied by 10 to the power 10 newton per meter square.
01:47
So this becomes the answer for this problem.
01:50
So this become the youngs modulus of the material...