00:01
For part a of the given problem, in order to find the resistance, we use an equation that is i is equal to enod.
00:09
Mf divided by impedance, z.
00:13
From here, we substitute the value for impedance, that is enod divided by square root of r square, plus xl minus xc square.
00:27
Then we find resistance from here.
00:31
In order to find resistance, we find xl and then xc.
00:37
To find xl and c, we find a frequency.
00:40
Frequency is one over time period.
00:44
So for a given time period, 0 .001, we get a frequency of 10 ,000 hertz.
00:53
10 ,000 hertz.
00:55
Next up, we find a capacity.
00:59
Which is 1 divided by 4 pi square f square times l this gives us by substituting a value for f and l we get 1 .26 times 10 to the power minus 6 for rod then in our next step we find xl which is omega times l that is 2 pi f times l so substituting a value for l and we get 12 .56 oms.
01:39
For then xc we already found a frequency and capacitance we'll use that and find xc which is 1 divided by 2 pi f times c this will give us 12 .63 oms...