00:01
For this problem, we're given the graph of the velocity versus time, the velocity on one dimension versus the time.
00:10
And first of all, we're asked to compute the average acceleration for the time interval between t equals zero.
00:23
From the definition of the average velocity, we know the average velocity, the average acceleration, my apologies.
00:32
The average acceleration is the rate or change of the average velocity over the changing time.
00:39
And the time interval is 6 minus 0.
00:43
And looking from the graph, the velocity of 6 second is 8, and the velocity of 0 second is 0.
00:52
So we get an average acceleration of 1 .33 meters per second square.
01:01
Then for the next question, which is b, we want to find out, we want to estimate the time of which the acceleration has its greatest positive value, and the value of the acceleration at that instant.
01:18
The greatest positive value occurs at t equals three seconds.
01:25
This happens that t equals three seconds.
01:32
And the value is obtained by computing the slope of the tangent line in between four and two seconds...