00:01
High -franchier is given a three -dimensional scale of very fine crystals.
00:07
The dotted line illustrates how a thin parallel faces flap of material could be cut from a larger spaceway with the optic axis of the crystal paladin to the face of the plate.
00:22
A section cut from the crystal in the manner is known as a tradition place when a beam of life is incident on the plane perpendicular direction to the optic axis as shown in the figure.
00:40
The o ray and e ray travel along a single straight line but with a different space.
00:49
Let the thickness of the plate deal and so that the phase difference between o and e.
00:55
We have to prove that phase difference between o ray and e ray.
01:22
Is 2x5d upon wavelength reflective index of o ray and reflective index of e -race this is a part and b part find the minimum value of the find the minimum for incident like heavy wavelength for light of wavelength 550 nanometer and theta to be 90 degrees.
02:35
Let us start solving it.
02:38
Part a, we will start with part a.
02:48
E and o ray will have a phase difference of e and o ray will have a phase difference.
03:21
The data is the path difference.
03:25
The optical part difference between the two points is the product of actual path and respective index...