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Figure $P 15.49$ shows a closed cylincler with cross-sectional area $A=2.00 \mathrm{m}^{2}$ . The con- stant clectric ficld $\overrightarrow{\mathrm{E}}$ has magnitude $3.50 \times 10^{3} \mathrm{N} / \mathrm{C}$ and is directed vertically upward, perpendicular to the cylinder's top and bottom surfaces so that no field lines pass through the curved surface. Calculate the electric flux

through the cylinder's (a) top and (b) bottom surfaces. (c) Determine the amount of charge inside the cylinder.

a. $7 \times 10^{3} \mathrm{N} . \mathrm{m}^{2} / \mathrm{C}$

b. $7 \times 10^{3} \mathrm{N} \cdot \mathrm{m}^{2} / \mathrm{C}$

c. 0

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Hope College

Selander has gone across sexual area here off two meter square to meet it square, and the flux is passing through it. So the cylinder through this area and we are asked to find in part Jerry, what is the flux through the talk? Don't talk, and in part we were asked to find what is the flux for the bottom? So the flex through the bar a top wouldn't be a flux by definition of flux. We know electric field times, the times that costs data. So the flux here is making zero angle there Day zero, with the flux going out from the stop. So they are in voter thesis, the direction off the surface and the direction off the electric field is again in this direction. So then the zero and we can write the flux will be simply eat times, eh? From here, I'll substitute the values. These are 3.5 old time stands for three times the idea to excuse us. The flocks off seven times gentle, our three Newton meters square hula. It's really for the tall at the bottom, the bottom, uh, the salmon flux. He's going through the bottom, so the flux will be again seven times. 10 to power. Three Newton Meters Square Park. Cool. But see, since there are no charges in the cylinder, never for Ah, I mean, the flax is going in and going out, so no charges. So the charges will be, is it'll?